Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example:Given the below binary tree and
sum = 22, 5
/ \
4 8
/ / \
11 13 4
/ \ / \
7 2 5 1
return
[ [5,4,11,2], [5,8,4,5] ]
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void check(TreeNode *root, vector<int> v, vector<vector<int> > &result, int current_sum, int target_sum)
{
if(!root)
return;
current_sum += root->val;
v.push_back(root->val);
if(!root->left && !root->right)
{
if(current_sum == target_sum)
result.push_back(v);
return ;
}
check(root->left, v, result, current_sum, target_sum) ;
check(root->right, v, result, current_sum, target_sum);
}
vector<vector<int> > pathSum(TreeNode *root, int sum) {
vector<int> v;
vector<vector<int> > vr;
check(root, v, vr, 0, sum);
return vr;
}
};
No comments:
Post a Comment