Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
The same repeated number may be chosen from C unlimited number of times.
Note:
- All numbers (including target) will be positive integers.
- Elements in a combination (a1, a2, � , ak) must be in non-descending order. (ie, a1 ? a2 ? � ? ak).
- The solution set must not contain duplicate combinations.
For example, given candidate set
A solution set is:
2,3,6,7 and target 7, A solution set is:
[7] [2, 2, 3] [0,1,0,2,1,0,1,3,2,1,2,1],void generate(vector<int> v, int current_sum, int target, int i, vector<int> &candidates, vector<vector<int> > &results) { if(current_sum == target) { results.push_back(v); return; } if(i >= candidates.size() || current_sum > target) return; generate(v, current_sum, target, i+1, candidates, results); v.push_back(candidates[i]); generate(v, current_sum + candidates[i], target, i, candidates, results); } vector<vector<int> > combinationSum(vector<int> &candidates, int target) { vector<int> v; vector<vector<int> > results; sort(candidates.begin(), candidates.end()); generate(v, 0, target, 0, candidates, results); return results; }
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